4x + 3y = 6 -4x + 2y = 14 Solve the system of equations. A) x = 1 2 , y = 3 B) x = 3, y = 1 2 C) x = 4, y = - 3 2 D) x = - 3 2 , y = 4

The solution of the system of equations is [tex]x=\frac{-3}{2}[/tex] , y = 4 ⇒ DStep-by-step explanation:To solve the system of equation we can use on of two methodsElimination methodSubstitution methodThe system of equation is:4x + 3y = 6 ⇒ (1)-4x + 2y = 14 ⇒ (2)Let us use the elimination method because the coefficients of x in the two equations have same values and different signs, so they eliminate each otherAdd equations (1) and (2) to eliminate x∵ (4x + -4x) + (3y + 2y) = (6 + 14)∴ 5y = 20- Divide both sides by 5∴ y = 4Substitute the value of y in equations (1) or (2) to find xWe will substitute y in equation (1)∴ 4x + 3(4) = 6∴ 4x + 12 = 6- Subtract 12 from both sides∴ 4x = -6- Divide both sides by 4∴ [tex]x=\frac{-3}{2}[/tex]The solution of the system of equations is [tex]x=\frac{-3}{2}[/tex] , y = 4Learn more:You can learn more about the system of equations in brainly.com/question/6075514#LearnwithBrainly